Given the code fragment: Path path1 = Paths.get("/app/./sys/"); Path res1 = path1.resolve("log"); Path path2 = Paths.get("/server/exe/"); Path res1 = path1.resolve("/readme/"); System.out.println(res1); System.out.println(res2); What is the result?
Click on the arrows to vote for the correct answer
A. B. C. D.C.
The given code fragment creates two Path
objects, path1
and path2
, using the Paths.get()
method. Then, the resolve()
method is called on both path1
and path2
to create two new Path
objects, res1
and res2
, respectively. Finally, the toString()
method is called on both res1
and res2
to print their string representations to the console.
Let's look at each line of code and see what it does:
javaPath path1 = Paths.get("/app/./sys/");
This creates a Path
object path1
representing the directory /app/./sys/
. The .
in /app/./sys/
is a relative directory reference that means "the current directory", but it has no effect on the resulting Path
object.
javaPath res1 = path1.resolve("log");
This resolves the relative Path
"log"
against path1
, resulting in a new Path
object res1
representing the directory /app/./sys/log
. Again, the .
in /app/./sys/
has no effect on the resulting Path
object.
javaPath path2 = Paths.get("/server/exe/");
This creates a Path
object path2
representing the directory /server/exe/
.
javaPath res1 = path1.resolve("/readme/");
This resolves the absolute Path
"/readme/"
against path1
, resulting in a new Path
object res1
representing the directory /readme/
. The leading /
in "/readme/"
makes it an absolute path, which means it is resolved starting from the root directory.
javaSystem.out.println(res1); System.out.println(res2);
This prints the string representations of res1
and res2
to the console. Therefore, the output of the code will be:
javascript/readme/ /server/exe/readme
Therefore, the correct answer is option D: /app/./sys/log /server/exe/readme
.