Isolation Ward Patient Ages - Population Variance

Population Variance Calculation

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Question

The ages of all the patients in the isolation ward of the hospital are 38, 26, 13, 41 and 22. What is the population variance?

Answers

Explanations

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A. B. C. D. E.

B

Population variance = (Sum of squared deviation from the mean)/N. the mean is 28. Population variance = (100 + 4 + 225 + 169 + 36)/5 = 534/5 = 106.8 xx-mean(x-mean)^2

3810100

26-24

13-15225

4113169

22-636

To calculate the population variance, you need to follow these steps:

  1. Find the mean (average) of the data set.

    • Add up all the ages: 38 + 26 + 13 + 41 + 22 = 140.
    • Divide the sum by the number of data points (in this case, 5): 140 / 5 = 28.
    • The mean age is 28.
  2. Calculate the deviation from the mean for each data point.

    • For each age, subtract the mean (28) from the age itself.
      • Deviation for 38: 38 - 28 = 10
      • Deviation for 26: 26 - 28 = -2
      • Deviation for 13: 13 - 28 = -15
      • Deviation for 41: 41 - 28 = 13
      • Deviation for 22: 22 - 28 = -6
  3. Square each deviation.

    • Square each deviation you calculated in the previous step.
      • Squared deviation for 10: 10^2 = 100
      • Squared deviation for -2: (-2)^2 = 4
      • Squared deviation for -15: (-15)^2 = 225
      • Squared deviation for 13: 13^2 = 169
      • Squared deviation for -6: (-6)^2 = 36
  4. Find the sum of squared deviations.

    • Add up all the squared deviations.
      • Sum of squared deviations = 100 + 4 + 225 + 169 + 36 = 534.
  5. Divide the sum of squared deviations by the number of data points (population size).

    • Divide the sum of squared deviations (534) by the number of data points (5).
    • Population variance = 534 / 5 = 106.8.

Therefore, the population variance of the ages in the isolation ward is 106.8.

The correct answer from the provided options is B. 106.8.