Events X and Y are mutually exclusive. P(X) = 0.15, P(Y) = 0.32. The probability of either X or Y occurring equals ________.
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A. B. C. D.C
Note the relationship, P(X or Y) = P(X) + P(Y) - P(X and Y) Also remember that for mutually exclusive events, by definition, P(X and Y) = 0. Therefore, P(X or Y) =
0.15 + 0.32 = 0.47.
To determine the probability of either event X or event Y occurring, we need to consider the concept of mutually exclusive events.
Mutually exclusive events are events that cannot occur simultaneously. In other words, if event X happens, event Y cannot happen, and vice versa. This implies that the probability of both events occurring together is zero.
In this case, we are given the individual probabilities of event X and event Y occurring. P(X) = 0.15 and P(Y) = 0.32.
Since events X and Y are mutually exclusive, the probability of either X or Y occurring can be calculated by adding their individual probabilities:
P(X or Y) = P(X) + P(Y)
Substituting the given probabilities, we have:
P(X or Y) = 0.15 + 0.32
P(X or Y) = 0.47
Therefore, the probability of either event X or event Y occurring is 0.47.
The correct answer is C. 0.47.