David's gasoline station offers 4 cents off per gallon if the customer pays in cash and does not use a credit card. Past evidence indicates that 40% of all customers pay in cash. During a one-hour period twenty-five customers buy gasoline at this station. What is the probability that at least ten pay in cash?
Click on the arrows to vote for the correct answer
A. B. C. D. E.B
This is a binomial distribution: n!(p^r)(q^(n-r))/r!(n-r)!. n = 25, r = 10, p = 0.4 q = 0.6
P(10) = 25!(0.4^10)(0.6^15)/10!15! = 0.1612
P(11) = 25!(0.4^11)(0.6^14)/11!14! = 0.1465
P(12) = 25!(0.4^12)(0.6^13)/12!13! = 0.1140
P(13) = 25!(0.4^13)(0.6^12)/13!12! = 0.0760
P(14) = 25!(0.4^14)(0.6^11)/14!11! = 0.0434
P(15) = 25!(0.4^15)(0.6^10)/15!10! = 0.0212
P(16) = 25!(0.4^16)(0.6^9)/16!9! = 0.0088
P(17) = 25!(0.4^17)(0.6^8)/17!8! = 0.0031
Summing up we get close to 0.574.
We can continue until r = 25 but the probability gets smaller and converges to 0.575.