Probability of Regular Reading by Top Executives

D

35% + 40% - 10% = 65%

To solve this problem, we can use the principle of inclusion-exclusion.

Let's define the following events: A = The event that a top executive reads Time magazine regularly. B = The event that a top executive reads Newsweek regularly. C = The event that a top executive reads U.S. News & World Report regularly.

We are given the following probabilities: P(A) = 0.35 (35% read Time magazine) P(B) = 0.20 (20% read Newsweek) P(C) = 0.40 (40% read U.S. News & World Report) P(A ∩ C) = 0.10 (10% read both Time and U.S. News & World Report)

We need to find the probability that a top executive reads either Time or U.S. News & World Report regularly, which can be represented as P(A ∪ C).

Using the principle of inclusion-exclusion, we can calculate this probability as follows:

P(A ∪ C) = P(A) + P(C) - P(A ∩ C)

P(A ∪ C) = 0.35 + 0.40 - 0.10 = 0.75

Therefore, the probability that a particular top executive reads either Time or U.S. News & World Report regularly is 0.75.

However, none of the provided answer choices matches this result. Therefore, the correct answer is C. None of these answers.