Question 216 of 367 from exam 200-301-CCNA: Implementing and Administering Cisco Solutions
Question
Refer to the exhibit.
Which address and mask combination represents a summary of the routes learned by EIGRP?
![Gateway of last resort is not set
D
D
D
D
c
c
192.168.25.0/30 is subnetted, 4 subnets
192.168.25.20 [90/2681856] via 192.168.15.5, 00:00:10, Serial0/1
192.168.25.16 [90/1823638] via 192.168.15.5, 01
192.168.25.24 [90/3837233] via 192.168.15.5, 01
192.168.25.28 [90/8127323] via 192.168.15.5, 00:
192.168.15.4/30 is directly connected, Serial0/1
192.168.2.0/24 is directly connected, FastEthernet0/0
10, Serial0/1
3, Serial0/1
345, Serial0/1](https://eaeastus2.blob.core.windows.net/optimizedimages/static/images/Cisco-Certified-Network-Associate-(CCNA)/question/img0015900001.png)
Answers
Explanations
Click on the arrows to vote for the correct answer
A. B. C. D. E. F.C.
The binary version of 20 is 10100
The binary version of 16 is 10000
The binary version of 24 is 11000
The binary version of 28 is 11100
The subnet mask is /28
The mask is 255.255.255.240
Note: From the output above, EIGRP learned 4 routes and we need to find out the summary of them: ->192.168.25.16 192.168.25.20
/answer/img0015900003.png)
->192.168.25.24 ->192.168.25.28 -> The increment should be 28 ?16 = 12 but 12 is not an exponentiation of 2; so we must choose 16 (24)
Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) = 255.255.255.240
So the best answer should be 192.168.25.16 255.255.255.240.