Question 3 of 32 from exam 300-215-CBRFIR: Conducting Forensic Analysis and Incident Response Using Cisco Technologies for CyberOps

Question 3 of 32 from exam 300-215-CBRFIR: Conducting Forensic Analysis and Incident Response Using Cisco Technologies for CyberOps

Question

351.613329
351,614781
351.615356
351.615473
351.616366
351.617248
351.618094
351.618857
351.619789,
351,620622
351.621398
351,622245
351.623161
351.624003
351.624765

Source
167.203.102.117

227.161.2158
209.92.25.229
149.221.46.147
192.183.44.102
162.178.159.141
203.98.141.133,
115.48.48.185
147.29.251.74
29.158.7.85
133.119.25.131
89,99.115.209
221.19.65.45
124.97.107.209
140.147.97.13

[Destination
192.168.1.159

192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159
192.168.1.159

15120 —> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
15409 > 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
15701 —> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
18969 -> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
16247 —> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
16532 —> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
16533 > 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
16718 > 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
17009 -> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
17304 -> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
17599 -> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
17874 > 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
18160 —> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment
18448 —> 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment

18740 > 80 [SYN] Seq=0 Win=64 Len=120 [TCP segment

Refer to the exhibit.

What should an engineer determine from this Wireshark capture of suspicious network traffic?

Answers

Explanations

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A. B. C. D.

A.