Storing Months of a Year: Best Option for Performance | CompTIA IT Fundamentals Exam

Best Option for Storing Months of a Year with Performance in Mind

Question

Which of the following is the BEST option for a developer to use when storing the months of a year and when performance is a key consideration?

Answers

Explanations

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A. B. C. D.

A.

When performance is a key consideration for storing the months of a year, the best option for a developer would be to use an array.

An array is a data structure that stores a fixed-size sequential collection of elements of the same type. In an array, each element can be accessed directly by its index or position in the collection. Arrays provide fast and efficient access to their elements, making them an ideal choice when performance is a key consideration.

In the case of storing the months of a year, an array of strings can be used. Since there are 12 months in a year, the array can be initialized with a size of 12, with each element representing a month. For example:

go
string[] months = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};

Arrays have a fixed size, which means that the size of the array cannot be changed once it is created. However, this is not a limitation when storing the months of a year since the number of months is fixed at 12.

Vectors and lists are also data structures that can be used to store a collection of elements, but they are not the best options when performance is a key consideration. Vectors are similar to arrays, but they can dynamically resize themselves, which makes them slower than arrays. Lists, on the other hand, provide flexibility in terms of adding or removing elements from the list, but they are slower than arrays and vectors when accessing individual elements.

A string is not an appropriate data structure to store a collection of months since it is a sequence of characters, not a collection of elements. It would be possible to store the months as a concatenated string, but this would not be an efficient way to store or access the data.