The distribution of the annual incomes of a group of middle management employees approximated a normal distribution with a mean of $37,200 and a standard deviation of $800. About 68 percent of the incomes lie between what two incomes?
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A. B. C. D. E.A
68/2 = 0.34. The z value for 0.34 is 1. x = u +/- z*sigma. So x = 37200 +/- 1*800. e get x = 38,000 and 36,400.
To determine the range within which 68 percent of the incomes lie, we can use the concept of the empirical rule, also known as the 68-95-99.7 rule. According to this rule, for a normal distribution:
In this case, we are given a normal distribution with a mean of $37,200 and a standard deviation of $800. Since we are looking for the range within one standard deviation, we can calculate the lower and upper bounds as follows:
Lower bound = Mean - Standard deviation Upper bound = Mean + Standard deviation
Lower bound = $37,200 - $800 = $36,400 Upper bound = $37,200 + $800 = $38,000
Therefore, approximately 68 percent of the incomes lie between $36,400 and $38,000.
The correct answer is option A: $36,400 and $38,000.