What annual interest rate, compounded annually, will cause an original deposit of $500 to grow to $625, after 3 years?
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A. B. C. D. E.D
On the BAII Plus, press 500 PV, 625 +/- FV, 0 PMT, 3 N, then CPT I/Y. On the HP12C, press 500 PV, 625 CHS FV, 0 PMT, 3 n, then press i.
To determine the annual interest rate that will cause an original deposit of $500 to grow to $625 after 3 years, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where: A = the future value of the deposit P = the initial deposit amount r = the annual interest rate (in decimal form) n = the number of times interest is compounded per year t = the number of years
In this case, we know the initial deposit is $500 (P = $500), the future value is $625 (A = $625), the number of years is 3 (t = 3), and the interest is compounded annually (n = 1).
Now we can plug in the values into the formula and solve for r:
$625 = $500(1 + r/1)^(1*3)
Simplifying further:
$625 = $500(1 + r)^3
Divide both sides by $500:
1.25 = (1 + r)^3
To isolate (1 + r), we can take the cube root of both sides:
(1 + r) = (1.25)^(1/3)
Using a calculator, we find that (1.25)^(1/3) is approximately 1.0905.
Subtracting 1 from both sides:
r = 1.0905 - 1
r = 0.0905
Finally, we convert the decimal form to a percentage:
r = 0.0905 * 100%
r ≈ 9.05%
Therefore, the annual interest rate, compounded annually, that will cause an original deposit of $500 to grow to $625 after 3 years is approximately 9.05%.
Among the answer choices provided, the closest option is B. 9.14%.