Subnet Mask for 172.45.32.6/19

C

The subnet mask determines the network and host portions of an IP address. It is a 32-bit number used to divide an IP address into network and host portions. In this case, the IP address is 172.45.32.6/19, which means that the first 19 bits of the IP address are the network portion, and the remaining 13 bits are the host portion.

To find the subnet mask, we need to convert the number of network bits (19) to binary and fill the rest of the bits with 0's.

Step 1: Convert the number of network bits (19) to binary

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19 = 0001 0011 

Step 2: Fill the remaining bits with 0's

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0001 0011 0000 0000 

Step 3: Convert the binary number back to decimal

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0001 0011 0000 0000 = 240 

Therefore, the subnet mask for the 172.45.32.6/19 address is 255.255.240.0 (which represents 1111 1111 1111 1111 1111 0000 0000 0000 in binary).

Option A is the correct answer.