JNCIS Exam: Aggregate Routes for 10.10.14.0/24, 10.10.15.0/24, 10.10.16.0/24, and 10.10.17.0/24

Aggregate Routes for Juniper JN0-360 Exam

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Question

Click the Exhibit button.

10.10.14.0/24

10.10.15.0/24

10.10.16.0/24

10.10.17.0/24

Which aggregate route would represent all four routes shown in the exhibit?

Answers

Explanations

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A. B. C. D.

A

To represent all four routes, we need to find the most specific aggregate route that encompasses all the individual routes in the exhibit. To do this, we can use the following steps:

Step 1: Write out the binary representation of the subnet masks for each of the four routes:

makefile
10.10.14.0/24: 11111111.11111111.11111111.00000000 10.10.15.0/24: 11111111.11111111.11111111.00000000 10.10.16.0/24: 11111111.11111111.11111111.00000000 10.10.17.0/24: 11111111.11111111.11111111.00000000

Step 2: Identify the leftmost bit position where the binary representations of the subnet masks differ. This is the bit position at which we can create an aggregate route that encompasses all four individual routes.

In this case, the leftmost bit position where the subnet masks differ is the 19th bit (counting from the left), as shown below:

makefile
10.10.14.0/24: 11111111.11111111.11111111.00000000 10.10.15.0/24: 11111111.11111111.11111111.00000000 10.10.16.0/24: 11111111.11111111.11111111.00000000 10.10.17.0/24: 11111111.11111111.11111111.00000000 ------------------------------^

Step 3: Create an aggregate route that encompasses all four individual routes by setting all the bits to the left of the 19th bit to their maximum value (1), and setting all the bits to the right of the 19th bit to their minimum value (0):

makefile
10.10.0.0/19: 11111111.11111111.00000000.00000000

This route covers all the four routes, and is the most specific aggregate route that can represent all four of them.

Therefore, the correct answer is A. 10.10.0.0/19.