The weights (in kilograms) of a group of crates being shipped to Panama are 95, 103, 110, 104, 105, 112 and 92. What is the mean deviation?
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A. B. C. D. E.B
The mean is 103. The mean deviation is the absolute values of the deviation from the mean: (8 + 0 + 7 + 1 + 2 + 9 + 11)/7 = 38/7 = 5.43
To calculate the mean deviation, we first need to find the mean (average) of the weights of the crates.
Mean = (95 + 103 + 110 + 104 + 105 + 112 + 92) / 7 = 721 / 7 = 103 kg (rounded to the nearest whole number)
Next, we calculate the deviation of each weight from the mean. Deviation is the absolute difference between each weight and the mean.
Deviation from the mean for each weight: |95 - 103| = 8 |103 - 103| = 0 |110 - 103| = 7 |104 - 103| = 1 |105 - 103| = 2 |112 - 103| = 9 |92 - 103| = 11
Now, we calculate the mean deviation. Mean deviation is the average of the absolute deviations from the mean.
Mean deviation = (8 + 0 + 7 + 1 + 2 + 9 + 11) / 7 = 38 / 7 ≈ 5.43 kg
Therefore, the mean deviation of the weights is approximately 5.43 kg.
The correct answer is B. 5.43 kg.