Given an IP address 172.16.28.252 with a subnet mask of 255.255.240.0, what is the correct network address?
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A. B. C. D.A
For this example, the network range is 172.16.16.1 - 172.16.31.254, the network address is 172.16.16.0 and the broadcast IP address is 172.16.31.255.
To determine the network address for the given IP address and subnet mask, we need to perform a bitwise AND operation between the two.
Here are the steps to perform this operation:
IP address: 172.16.28.252 Binary: 10101100.00010000.00011100.11111100
Subnet mask: 255.255.240.0 Binary: 11111111.11111111.11110000.00000000
10101100.00010000.00010000.00000000
Binary: 10101100.00010000.00010000.00000000 Decimal: 172.16.16.0
Therefore, the correct network address for the given IP address and subnet mask is 172.16.16.0, which is option A.