A network administrator has been given a network of 172.16.85.0/21 and wants to know the usable range of IP addresses on that subnet.
Which of the following indicates the correct IP address range?
A.
172.16.80.0-172.16.85.254 B.
172.16.80.0-172.16.88.255 C.
172.16.80.1-172.16.87.254 D.
172.16.80.1-172.16.85.255
C.
A network administrator has been given a network of 172.16.85.0/21 and wants to know the usable range of IP addresses on that subnet.
Which of the following indicates the correct IP address range?
A.
172.16.80.0-172.16.85.254
B.
172.16.80.0-172.16.88.255
C.
172.16.80.1-172.16.87.254
D.
172.16.80.1-172.16.85.255
C.
The network address 172.16.85.0/21 has a subnet mask of 255.255.248.0, which means the network has 11 bits for host addresses, resulting in 2^11 - 2 = 2046 possible host addresses.
The formula to calculate the usable IP address range for a given subnet is:
Network address + 1 (for the first usable host address) to Broadcast address - 1 (for the last usable host address)
To calculate the network address, we need to convert the subnet mask to binary and perform a bitwise AND operation with the given IP address.
Subnet mask: 11111111.11111111.11111000.00000000 IP address: 10101100.00010000.01010101.00000000 &---------------------------------- Network address: 10101100.00010000.01010000.00000000 (172.16.80.0)
The broadcast address is the last address in the subnet, which can be calculated by setting all the host bits to 1:
11111111.11111111.11111111.11111111 (binary 1's)
Converting the binary 1's to decimal gives us 255.255.255.255, which is the broadcast address.
Therefore, the usable IP address range for the subnet 172.16.85.0/21 is:
172.16.80.1 - 172.16.87.254
Option C, 172.16.80.1-172.16.87.254, is the correct answer.