JN0-102 Exam: IPv4 Subnet Network ID Address Calculation

Network ID Address of IPv4 Subnet

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Question

What is the network ID address of the IPv4 subnet that includes the IP address 114.180.192.120/28?

Answers

Explanations

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A. B. C. D.

C

The given IPv4 address 114.180.192.120/28 is a Classless Inter-Domain Routing (CIDR) notation, which represents the IP address and subnet mask length in bits. In this case, the subnet mask length is 28 bits, which means that the first 28 bits of the IP address represent the network portion, and the remaining 4 bits represent the host portion.

To determine the network ID address of the given IPv4 subnet, we need to perform a bitwise logical AND operation between the IP address and the subnet mask. The subnet mask for a /28 subnet is 255.255.255.240, which is represented in binary as 11111111.11111111.11111111.11110000.

Converting the IP address 114.180.192.120 into binary form, we get: 01110010.10110100.11000000.01111000

Performing the bitwise logical AND operation between the IP address and subnet mask, we get: 01110010.10110100.11000000.01111000 (IP address) & 11111111.11111111.11111111.11110000 (Subnet mask)

01110010.10110100.11000000.01110000

Converting the result back to decimal form, we get the network ID address of the subnet: 114.180.192.112

Therefore, the correct answer is C. 114.180.192.112/28.