Customer's Router IP Address | N10-007 Exam Question | CompTIA Network+

192.168.1.55/24 Router IP Address

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Question

A technician is trying to determine the IP address of a customer's router.

The customer has an IP address of 192.168.1.55/24

Which of the following is the address of the customer's router?

A.

192.168.0.55 B.

192.168.1.0 C.

192.168.1.1 D.

192.168.5.5 E.

255.255.255.0

C.

Explanations

A technician is trying to determine the IP address of a customer's router.

The customer has an IP address of 192.168.1.55/24

Which of the following is the address of the customer's router?

A.

192.168.0.55

B.

192.168.1.0

C.

192.168.1.1

D.

192.168.5.5

E.

255.255.255.0

C.

The IP address provided, 192.168.1.55/24, indicates that the customer is using a Class C private IP address space, where the first three octets of the IP address (192.168.1) are reserved for the network, and the last octet (55) represents the host address. The /24 indicates that the subnet mask is 255.255.255.0, meaning that the first three octets of the IP address represent the network, and the last octet is available for host addresses.

To determine the address of the customer's router, we need to make an educated guess based on common router addresses. The router is typically the device that connects a local network to the internet, and its IP address is usually the first or last usable address in the subnet. In this case, the network address is 192.168.1.0 and the broadcast address is 192.168.1.255, so the router address is likely to be somewhere between them.

Option A, 192.168.0.55, is outside the customer's IP address range and subnet, so it's not a valid option.

Option B, 192.168.1.0, is the network address, which is not assignable to a device, so it's not a valid option.

Option C, 192.168.1.1, is a common default IP address for routers, so it's a valid option.

Option D, 192.168.5.5, is outside the customer's IP address range and subnet, so it's not a valid option.

Option E, 255.255.255.0, is the subnet mask, not an IP address, so it's not a valid option.

Therefore, the correct answer is C, 192.168.1.1.