Maximum Drives for Data Integrity in RAID 6 Configuration
Question
A technician has a server with ten hard drives in a RAID 6 configuration.
Which of the following is the MAXIMUM number of drives that can fail in the array while maintaining data integrity?
Answers
Explanations
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A. B. C. D.B.
RAID 6 is a type of redundant array of independent disks (RAID) that uses block-level data striping and dual distributed parity. This means that data is written across multiple disks in the array, and two separate sets of parity information are stored across the array to provide redundancy in case of disk failures.
In a RAID 6 array with ten hard drives, data is striped across eight drives, and two drives are used for parity. This means that the array can tolerate the failure of up to two drives without losing any data.
To calculate the maximum number of drives that can fail in a RAID 6 array while maintaining data integrity, we can use the formula:
n = m - 2
where n is the maximum number of drives that can fail, and m is the total number of drives in the array.
In this case, m = 10, so:
n = 10 - 2 = 8
Therefore, the maximum number of drives that can fail in a RAID 6 array with ten hard drives while maintaining data integrity is 2. The answer is B. 2.
