The probability that a value from a normal distribution will be less than 4 equals 83%. If the distribution has a mean of 2.2, the standard deviation of the distribution must be:
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A. B. C. D.Explanation
Using the Normal probability tables, the z-value of the observation, X, which can be exceeded with a probability of 17% equals 0.955. We are given that X = 4.
Now, the z-value of a selected observation, X, from a normal distribution with mean M and standard deviation S equals z = (X-M)/S. Therefore, 0.955 = (4 - 2.2)/S.
This gives S = 1.885.