Network Address for 10.13.147.100/19 Host

A

To determine the network address of a given IP address and subnet mask, we need to perform a bitwise logical AND operation between the two. This will give us the network address portion of the IP address.

In this case, the IP address is 10.13.147.100 and the subnet mask is /19. The subnet mask indicates that the first 19 bits of the IP address represent the network address, and the remaining 13 bits represent the host address.

To perform the bitwise AND operation, we need to convert the IP address and subnet mask to binary format and then perform the operation bit by bit. Here are the binary representations of the IP address and subnet mask:

IP address: 00001010.00001101.10010011.01100100 Subnet mask: 11111111.11111111.11100000.00000000

Bitwise AND: 00001010.00001101.10000000.00000000

Converting this back to decimal format, we get the network address for the given IP address and subnet mask:

Network address: 10.13.128.0

Therefore, the correct answer is A. 10.13.128.0.