Given the code fragment: Path p1 = Paths.get("/Pics/MyPic.jpeg"); System.out.println (p1.getNameCount() + ":" + p1.getName(1) + ":" + p1.getFileName()); Assume that the Pics directory does NOT exist.
What is the result?
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A. B. C. D.B.
The code fragment creates a Path object p1 for the file "/Pics/MyPic.jpeg". The getNameCount() method returns the number of name elements in the Path object. The getName(index) method returns the name element at the specified index, and the getFileName() method returns the file name of the Path object.
Since the Pics directory does not exist, the result depends on the operating system's file system behavior. In general, the file system may treat the non-existent directory as either an error condition or as a valid but empty directory.
Assuming that the file system treats the non-existent directory as a valid but empty directory, the result of the code fragment would be as follows:
The getNameCount() method would return 2 because the Path object has two name elements: "Pics" and "MyPic.jpeg". The getName(1) method would return the second name element, "MyPic.jpeg". The getFileName() method would also return "MyPic.jpeg".
Therefore, the output of the code fragment would be:
B. 2:MyPic.jpeg:MyPic.jpeg
If the file system treats the non-existent directory as an error condition, an exception would be thrown at run time, resulting in answer A.