Given the code fragments: class MyThread implements Runnable { private static AtomicInteger count = new AtomicInteger (0); public void run (){ int x = count.incrementAndGet(); System.out.print (x+" "); } } and Thread thread1 = new Thread(new MyThread()); Thread thread2 = new Thread(new MyThread()); Thread thread3 = new Thread(new MyThread()); Thread [] ta = {thread1, thread2, thread3}; for (int x= 0; x < 3; x++){ ta[x].start(); } Which statement is true?
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A. B. C. D.A.
The code defines a MyThread
class that implements the Runnable
interface and contains a static AtomicInteger
variable named count
. The run
method of MyThread
increments count
using the incrementAndGet()
method and prints the resulting value.
The code then creates three threads using the Thread
class and passing in a new instance of MyThread
as the target. The threads are stored in an array named ta
.
Finally, the code starts each thread in the ta
array by calling the start()
method on each thread in a loop.
Each thread created using MyThread
will increment the static count
variable and print the resulting value. Since count
is an AtomicInteger
, the increment operation is atomic and thread-safe, which means that multiple threads can safely increment the variable without interfering with each other.
The order in which the threads execute is unpredictable, so the output may not be in order. However, each thread will print a unique value because of the incrementAndGet()
method, which returns the new value of the AtomicInteger
after the increment operation.
Therefore, the correct answer is A. The program prints 1 2 3, and the order is unpredictable.