List of User Names and Login Shells from /etc/passwd

D

The correct answer is D. cut -d: -f1,7 /etc/passwd.

Explanation: The file /etc/passwd contains user account information on a Linux system, including the login shell for each user. To generate a list of user names from /etc/passwd along with their login shell, we can use the cut command.

The cut command is used to extract specific columns from a file. In this case, we want to extract the first and seventh columns from /etc/passwd. We can specify the delimiter between columns using the -d option. In this case, the delimiter is a colon (:). We can specify the columns we want to extract using the -f option.

So, the correct command to generate a list of user names from /etc/passwd along with their login shell is:

bashCopy code
cut -d: -f1,7 /etc/passwd 

This will output a list of user names followed by their login shell, separated by a colon (:). For example:

javascriptCopy code
root:/bin/bash daemon:/usr/sbin/nologin bin:/usr/sbin/nologin sys:/usr/sbin/nologin ... 

Option A (column -s : 1,7 /etc/passwd) would generate output in tabular format, but it would not separate the user names and login shells with a colon (:), as required.

Option B (chop -c 1,7 /etc/passwd) and option C (colrm 1,7 /etc/passwd) are not valid commands and would result in an error.